Are the following bicarbonate & phosphate calculations correct

1 mol sodium citrate à 3 mol soda bicarbonate Mr. Sodium citrate = 258.068 g/mol Mr sodium bicarbonate = 84.006 g/mol # mol NaHCO3 = 1g/84.006 g/mol = 0.0119039 mol #mol NaCitr = 0.0119039 mol/3 = 0.00396797 mol #g NaCitr = 0.00396797 mol X Mr = 1.02 g In my opinion, this can also be just in capsules together with a mannitol or sorbitol. Phosphate syrup: How much mmol phosphate is right? Option 1 Na2HPO4 18.18 G NaH2PO4 5g ORANGE PEEL SYRUP 100ml Aqua AD 300ml Convert: Mr Na2HPO4 = 141.957 g/mol Mr NaH2PO4 = 119.976 g/mol Mr PO43-= 94.97 g/mol #mol Na2HPO4 = 18.18 g/141.957 g/mol = 0.12806695 mol #mol NaH2PO4 = 5 g/119.976 g/mol = 0.04167500 mol # mol PO43-= # mol Na2HPO4 + # mol NaH2PO4 = 0.16974195 mol In 300 ml = 0.565 mmol/ml PO43- Or = 53.7 mg/ml PO43- This is true: 0.56 mmol Elementary P or PO43-(phosphate) per mL, what oveencomes with 53.2 mg PO43 or 15.5 mg Elementary P (phosphorus) Phosphate syrup, option 2: How much mmol phosphate is right? How much mmol K is right? Na2HPO4 73g Mono K phosphate 17.5 g Raspberries Extract 7 g After saccharin 0.3 g Sorbitol 120 g Aqua AD 300 ml Convert: Mr Na2HPO4 = 141.957 g/mol Mr KH2PO4 = 136.086 g/mol Mr PO43-= 94.97 g/mol Mr K + = 39.09 g/mol # mol Na2HPO4 = 7.3 g/141.957 g/mol = 0.051424023 mol à 73g/141.957 = 0514 mol # mol KH2PO4 = 17.5 g/= 136.086 g/mol = 0.12859515 mol # mol PO43-= # mol Na2HPO4 + # mol H2KPO4 = 0.18001918 mol à 0514 + 0128 mol = 0.64 mol 640 mmol at 300 mL thus gives 2.13 mmol P (Elemental phosphorus) or PO43-(phosphate) per mL, which corresponds to 66 mg P per mL and 202 mg PO43- IN 300 ml = 0.6 mmol/ml PO43- Or = 56.99 mg/ml PO43- # mol K + = # mol KH2PO4 = 0.12859515 mol In 300 ml = 0.428651 mmol/ml K + Or = 16.755948 mg/ml K +